The period of small oscillations of a simple pendulum of length λ if its point of suspension O moves a with a constant acceleration α = α 1
– α 2
with respect to earth is (
and
are unit vectors in horizontal and vertically upward directions respectively)
Text Solution
Verified by ExpertsThe correct answer is:
A
Point O is moving as shown

So acc. Of particle w.r.t O
= 
So g eff . = 
So time period
= 2 π 
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